x^2-4=(x+4)(x-4)

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Solution for x^2-4=(x+4)(x-4) equation: 


Simplifying
x2 + -4 = (x + 4)(x + -4)

Reorder the terms:
-4 + x2 = (x + 4)(x + -4)

Reorder the terms:
-4 + x2 = (4 + x)(x + -4)

Reorder the terms:
-4 + x2 = (4 + x)(-4 + x)

Multiply (4 + x) * (-4 + x)
-4 + x2 = (4(-4 + x) + x(-4 + x))
-4 + x2 = ((-4 * 4 + x * 4) + x(-4 + x))
-4 + x2 = ((-16 + 4x) + x(-4 + x))
-4 + x2 = (-16 + 4x + (-4 * x + x * x))
-4 + x2 = (-16 + 4x + (-4x + x2))

Combine like terms: 4x + -4x = 0
-4 + x2 = (-16 + 0 + x2)
-4 + x2 = (-16 + x2)

Add '-1x2' to each side of the equation.
-4 + x2 + -1x2 = -16 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-4 + 0 = -16 + x2 + -1x2
-4 = -16 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-4 = -16 + 0
-4 = -16

Solving
-4 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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